2017 WAEC FURTHER MATHS QUESTIONS AND ANSWERS

Spread the news

2017 WAEC FURTHER MATHS NO
1,4,5,9,10,11,12,14 ANSWERS
=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=
FURTHER MATHS OBJ
1-10. CBADCBADBB
11-20.DCBDCCDBCC
21-30. ACDCAABBCB
31-40. CDCDDBCAAD
1a)
g(x)=y
y=x 6
x=y-6
g^- f(x-6)
=4-5(x-6)/2=4-5x 30/2
=34-5x/2
1b)
coodinate=(x1 x2/2 ,y1 y2/2)
=(7-2/2,7-5/2)=(5/2,2/2)
=(5/2,1)
(4)
(x^2 5x 1)sqroot(2x^3 mx^2 nx 11)=(2x-5)
remainder:30x 16
(x^2 5x 1)(2x-5)
=2x^3 10x^2 2x-5x^2-25x-5
=2x^3 10x^2-5x^2-25x-5
=2x^3 5x^2-23x 30x 16-5
=2x^3 5x^2 7x 11
Therefore m=5, n=7

(9b)
At stationary points,
dy/dx=0.
y=x^0(x-3)
Let u=x^2,v=x-3.
du/dx=2x dv/dx=1.
dy/dx= Udv/dx Vdu/dx
dy/dx=x^2(1) (x-3)(2x)
.:. dy/dx=x^2 2x^2-6x
dy/dx=3x^2-6x
At stationary point,
dy/dx=0..
.:.3x^2-6x=0
Equation of line=> 3x^2-6x=0
10a)
i) (x^2-1) (x 2)=0
(x-1) (x 1) (x 2)
x=1, or -1 or -2
ii) 2x-3/(x-1)(x 1)( 2)
=A/x-1 B/x 1 C/x 2
2x-3=A(x 1)(x 2) B(x-1)(x 2)
C(x-1)(x 1)
let x 1=0,x=-1
2(-1)-3=B(-1-1)(-1 2)
-5/2=-2B/-2 B=5/2
let x-1 =0 x=1
2(1)-3=A(1 1)(1 2)
-1=CA, A=-1/6
Let x 2=0 x=-2
2(-2)-3=C(-2-1)(-2 1)
-7=3C, C=-7/3

(12a)
tabulate
Marks| 1-10, 11-20, 21-30, 31-40, 41-50,51-60,
61-70, 71-80, 81-90, 91-100
F| 3, 17, 41, 85, 97, 115, 101, 64, 21, 6
C.B| 0.5-105, 10.5-205, 20.5-305,
30.5-405,40.5-505, 50.5-605, 60.5-705,
70.5-805,80.5-905, 90.5-1005
C.F| 0 3=3, 3 17=20, 20 41=61, 61 85=146,146
77=243, 243 115=358, 358 101=459,459
64=523, 523 21=544, 544 6=550


Spread the news

Be the first to comment

Leave a Reply

Your email address will not be published.


*